Given an array of integers heights representing the histogram’s bar height where the width of each bar is 1, return the area of the largest rectangle in the histogram.
Input and output examples
Example 1:
Input: heights = [2,1,5,6,2,3] Output: 10 Explanation: The above is a histogram where width of each bar is 1. The largest rectangle is shown in the red area, which has an area = 10 units.
Example 2:
Input: heights = [2,4] Output: 4
Constraints:
1 <= heights.length <= 105 0 <= heights[i] <= 104
Solution
class Solution(object): def largestRectangleArea(self, heights): """ :type heights: List[int] :rtype: int """ if not heights: return 0 stack = [] max_area = 0 for i in range(len(heights)): if not stack or heights[i] >= heights[stack[-1]]: stack.append(i) else: while stack and heights[i] < heights[stack[-1]]: h = heights[stack.pop()] w = i if not stack else i - stack[-1] - 1 max_area = max(max_area, h * w) stack.append(i) while stack: h = heights[stack.pop()] w = len(heights) if not stack else len(heights) - stack[-1] - 1 max_area = max(max_area, h * w) return max_area
Test the the solution:
s = Solution() print(s.largestRectangleArea([2,1,5,6,2,3])) print(s.largestRectangleArea([2,4])) print(s.largestRectangleArea([2,4,5,6,7,8,9])) print(s.largestRectangleArea([9,8,7,6,5,4,3,2,1])) print(s.largestRectangleArea([1,2,3,4,5,6,7,8,9]))
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